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0.0504-0.336x+0.56x^2=x^2
We move all terms to the left:
0.0504-0.336x+0.56x^2-(x^2)=0
determiningTheFunctionDomain 0.56x^2-x^2-0.336x+0.0504=0
We add all the numbers together, and all the variables
-0.44x^2-0.336x+0.0504=0
a = -0.44; b = -0.336; c = +0.0504;
Δ = b2-4ac
Δ = -0.3362-4·(-0.44)·0.0504
Δ = 0.2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.336)-\sqrt{0.2016}}{2*-0.44}=\frac{0.336-\sqrt{0.2016}}{-0.88} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.336)+\sqrt{0.2016}}{2*-0.44}=\frac{0.336+\sqrt{0.2016}}{-0.88} $
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